PHYSICS
JAMB 2014 - Question 37
Physics 2014 JAMB Past Questions - Question 37: If a metal wire 4m long and cross sectional area 0.8mm² has a resistance of 60.find the resistivity of the wire .
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
B
Explanation
Resistivity, p = RA/t=6x0.8x10-6 = 1.2x10-6 Ω To find the resistivity of the wire, we can use the formula:
Resistance (R) = (Resistivity (ρ) * Length (L)) / Cross-sectional Area (A)
Given:
Resistance (R) = 6 Ω
Length (L) = 4 m
Cross-sectional Area (A) = 0.8 mm² = 0.8 × 10^(-6) m²
Substituting these values into the formula, we can solve for the resistivity (ρ):
6 Ω = (ρ * 4 m) / (0.8 × 10^(-6) m²)
Rearranging the equation, we get:
ρ = (6 Ω * 0.8 × 10^(-6) m²) / 4 m
Simplifying the expression, we find:
ρ = 1.2 × 10^(-6) Ω·m²
Therefore, the resistivity of the wire is 1.2 × 10^(-6) Ω·m².

