PHYSICS

JAMB 2006 - Question 36

Physics 2006 JAMB Past Questions - Question 36: A progressive wave equation is represented by y = a sin (150 rrt - rrx/4) If the phase difference of a progressive wave is 45, the value of x in the equation is

Choose the correct answers from the options given.
A progressive wave equation is represented by y = a sin (150 rrt - rrx/4) If the phase difference of a progressive wave is 45, the value of x in the equation is
A:
B:
C:
D:
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Correct Answer

B

Explanation

To find the value of x in the given progressive wave equation when the phase difference is 45 degrees, we can use the following equation:

Phase Difference (ΔΦ) = 45 degrees = π/4 radians

The phase difference in the given equation is represented by the term inside the sine function:

ΔΦ = 150 rrt - rrx/4

We want to solve for x. First, let's isolate the x term on one side:

ΔΦ = 150 rrt - rrx/4

ΔΦ = rrt(150 - x/4)

Now, we'll isolate x:

ΔΦ = 150 rrt - (rrt)x/4

Now, we can solve for x:

ΔΦ = (150 - x/4) rrt

x/4 = 150 - ΔΦ/rrt

x = 4(150 - ΔΦ/rrt)

Now, plug in the given phase difference ΔΦ = π/4 radians and the values of r and t, if available, to find the value of x. If you have specific values for r and t, you can calculate x accordingly.