PHYSICS
JAMB 2002 - Question 36
Physics 2002 JAMB Past Questions - Question 36: When connected to a mains of 2.50V, the fuse rating in the piug of an electric device of 1 kW is
Correct Answer
A
Explanation
P=IV=1000=25*1I=4ATo determine the fuse rating for an electric device with a power rating of 1 kW (kilowatt) when connected to a mains voltage of 2.50V, you'll need to use the formula:
Fuse rating (in amperes) = Power (in watts) / Voltage (in volts)
In this case, the power is 1 kW, which is equivalent to 1000 watts, and the voltage is 2.50V. Plug these values into the formula:
Fuse rating = 1000 watts / 2.50V = 400 amperes
So, the fuse rating for the electric device when connected to a mains voltage of 2.50V is 400 amperes. Please note that 400 amperes is a very high current rating, and typical household circuits are not designed for such high currents. Make sure that you have the appropriate electrical infrastructure to handle such a load, and consult a qualified electrician for safety and compliance with local electrical codes.

