PHYSICS
JAMB 2004 - Question 34
Physics 2004 JAMB Past Questions - Question 34: The change in vc when 450kg of ice is completely melted is < density of ice = 900kgm-³ density of water = 1000kgm-³
Correct Answer
A
Explanation
AV=Vice-V Water =m/Dice -m/Dw=450/900 -450/1000 =0.05m3To calculate the change in volume (ΔV) when 450 kg of ice is completely melted, you need to consider the difference in density between ice and water.
First, calculate the initial volume (V_ice) of the 450 kg of ice using the density of ice:
V_ice = mass / density
V_ice = 450 kg / 900 kg/m³
V_ice = 0.5 m³
Now, calculate the volume (V_water) of the same mass of water using the density of water:
V_water = mass / density
V_water = 450 kg / 1000 kg/m³
V_water = 0.45 m³
The change in volume (ΔV) is the difference between the volume of water and the initial volume of ice:
ΔV = V_water - V_ice
ΔV = 0.45 m³ - 0.5 m³
ΔV = -0.05 m³
The change in volume when 450 kg of ice is completely melted is -0.05 cubic meters. This negative value indicates that the volume decreases as the ice melts, and the ice turns into water.

