PHYSICS
JAMB 2010 - Question 29
Physics 2010 JAMB Past Questions - Question 29: An object 4cm high is placed 15cm . The size of the image is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
D
Explanation
(1)/v + (1)/u = (1)/f
(1)/v + (1)/15 = (1)/5
(1)/v = (1)/5 - (1)/15 = (3 - 1)/15 = (2)/15
∴ v = (15)/2 = 7.5 cm
magnification = (v)/u = (image size)/object size
(7.5)/15 = (X)/4
∴ image size. X = (7.5 x 4)/15 = 2 cm

