Physics 2002 JAMB Past Questions - Question 29: If tension is maintained on a stretched string of length 0.6m, such that its fundamental frequency of 220Hz is excited, determine the velocity of the transverse wave in the string.

Correct Answer

C

Explanation

y=2L ,V =YF ;v=2*0.6*220=264m/sThe velocity of a transverse wave on a string is given by the equation:

\[v = fλ\]

Where:
- \(v\) is the velocity of the wave.
- \(f\) is the frequency of the wave.
- \(λ\) is the wavelength of the wave.

To find the velocity of the wave, you need to determine the wavelength. For a fundamental frequency, the wavelength is twice the length of the string (\(λ = 2L\)), where \(L\) is the length of the string.

In your case, the length of the string (\(L\)) is 0.6 meters, and the frequency (\(f\)) is 220 Hz. So, the wavelength (\(λ\)) is:

\[λ = 2L = 2 * 0.6m = 1.2m\]

Now, you can use the equation to find the velocity (\(v\)):

\[v = fλ = 220 Hz * 1.2m = 264 m/s\]

So, the velocity of the transverse wave in the string is 264 meters per second.