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MATHEMATICS

JAMB 2003 - Question 29

Mathematics 2003 JAMB Past Questions - Question 29: Find the value of P ,if the line which passes through (-1,-p) and (-2p,2) is parrallel to the line 2y+8x-17=0.

Find the value of P ,if the line which passes through (-1,-p) and (-2p,2) is parrallel to the line 2y+8x-17=0.

A: 7/6

B: 6/7

C: -2/7

D: -6/7

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Correct Answer

Explanation

To find the value of P, we need to determine the slope of the line passing through (-1, -P) and (-2P, 2) and compare it to the slope of the line 2y + 8x - 17 = 0.The slope of a line can be found using the formula:slope = (yâ‚‚ - yâ‚�) / (xâ‚‚ - xâ‚�)For the line passing through (-1, -P) and (-2P, 2), we have:slope = (2 - (-P)) / (-2P - (-1)) = (2 + P) / (-2P + 1)Since the line is parallel to the line 2y + 8x - 17 = 0, the slopes of the two lines must be equal. Therefore, we can equate the slopes:(2 + P) / (-2P + 1) = -8/2Simplifying the equation:(2 + P) / (-2P + 1) = -4Cross-multiplying:(2 + P) * 2 = (-2P + 1) * -4Expanding:4 + 2P = 8P - 4Rearranging the terms:6P = 8Dividing both sides by 6:P = 8/6Simplifying:P = 4/3Therefore, the value of P is 4/3.