PHYSICS

JAMB 2017 - Question 28

Physics 2017 JAMB Past Questions - Question 28: In a sound wave in air, the adjacent rare-fractions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms¹ determine the frequency .

Choose the correct answers from the options given.
In a sound wave in air, the adjacent rare-fractions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms¹ determine the frequency .
A:
B:
C:
D:
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Correct Answer

D

Explanation

To determine the frequency of the sound wave, we can use the formula:

velocity = frequency × wavelength

Given that the velocity of the sound wave is 340 m/s and the distance between adjacent rarefactions and compressions (wavelength) is 17 cm (which is equal to 0.17 m), we can rearrange the formula to solve for frequency:

frequency = velocity / wavelength

Substituting the given values:

frequency = 340 m/s / 0.17 m
frequency ≈ 2000 Hz

Therefore, the frequency of the sound wave is approximately 2000 Hz.