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MATHEMATICS

JAMB 2011 - Question 28

Mathematics 2011 JAMB Past Questions - Question 28: In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.

In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.

A: 70°

B: 55°

C: 40°

D: 35°

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Correct Answer

Explanation

PQRS is a cyclic quad^P = 180 - 110 (opp ∠s of a cyclic quad)^P = 70In ΔPTS, ^S = ^T (base ∠s of Isc Δ)∴^T = (180-70) / 2= 110/2= 55°But ^T x(corr ∠)∴x =55