Physics 2022 JAMB Past Questions - Question 26: A gas at a volume of Vo in a container at pressure Po is compressed to one-fifth of its volume. What will be its pressure if the magnitude of its original temperature T is constant?

Correct Answer

D

Explanation

If the gas is compressed to one-fifth of its original volume while the magnitude of its temperature remains constant, we can use the combined gas law to find the new pressure. The combined gas law states that the ratio of the initial pressure to the final pressure is equal to the ratio of the initial volume to the final volume, when the temperature is held constant.

Mathematically, this can be expressed as:

P1 * V1 = P2 * V2

Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume

Given that the gas is compressed to one-fifth of its original volume, V2 = (1/5) * Vo. Since the temperature T is constant, we can use the combined gas law to solve for P2:

P1 * V1 = P2 * V2
Po * Vo = P2 * (1/5) * Vo

Solving for P2:

P2 = 5 * Po

Therefore, the pressure of the gas will be 5 times its original pressure, assuming the magnitude of its original temperature remains constant.