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PHYSICS

JAMB 2014 - Question 26

Physics 2014 JAMB Past Questions - Question 26: The distance between two successive crests of a wave is 15cm and velocity 300ms Calculate the frequency.

Choose the most appropriate option for the gap .

The distance between two successive crests of a wave is 15cm and velocity 300ms Calculate the frequency.

A: 4.5x10-µHz

B: 2.0x10-³Hz

C: 4.5x10-²Hz

D: 2.0x10-²Hz

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Correct Answer

Explanation

Distance between time successive crests = wavelength, = 15cm = 0.15mvelocity, V=300m/sbut v= f where f = frequency .f =vtherefore f=V= 300/0.15 = 2000Hz - 2x103Hz