ENGLISH

JAMB 2013 - Question 26

Mathematics 2013 JAMB Past Questions - Question 26: If the angles of a quadrilateral are (3y+10),(2y+30),(y+20) and 4y,find the value of y.

If the angles of a quadrilateral are (3y+10),(2y+30),(y+20) and 4y,find the value of y.
A:
B:
C:
D:
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Correct Answer

C

Explanation

(3y +10) + (2y+30) +(y+20) +4y= (2n - 4) 00, where n = 4thus, (3y+10) +(2y+30)+(y+20) +4yIn a quadrilateral, the sum of all interior angles is equal to 360 degrees. Given the angles of the quadrilateral as (3y + 10), (2y + 30), (y + 20), and 4y, we can set up an equation to find the value of y:(3y + 10) + (2y + 30) + (y + 20) + 4y = 360Simplifying the equation:3y + 10 + 2y + 30 + y + 20 + 4y = 36010y + 60 = 360Subtracting 60 from both sides:10y = 300Dividing both sides by 10:y = 30Therefore, the value of y is 30.= (2x4-4) 9010y +60 = (8-4)9010y +60 = 4x9010y +60 = 36010 y = 360 - 60 = 300y = 300 /10 = 30