MATHEMATICS

JAMB 2004 - Question 24

Mathematics 2004 JAMB Past Questions - Question 24: The sum of the interior angles of a pentagon is 6x+6y. Find in terms od x

The sum of the interior angles of a pentagon is 6x+6y. Find in terms od x
A:
B:
C:
D:
Examkits App

Examkit's JAMB CBT App

Practice JAMB offline with our Online, PC and Mobile App

  • ✅ 25+ years of past questions (2000 to 2025)
  • ✅ Video solutions and explanation to questions
  • ✅ E-library
  • ✅ Study by topic
  • ✅ And more.

Correct Answer

B

Explanation

The sum of the interior angles of a polygon can be calculated using the formula:Sum = (n - 2) * 180 degreeswhere n is the number of sides of the polygon.In this case, we have a pentagon, which has 5 sides. So, the sum of the interior angles of the pentagon is:Sum = (5 - 2) * 180 degrees    = 3 * 180 degrees    = 540 degreesWe are given that the sum of the interior angles is 6x + 6y. Therefore, we can equate this to 540 degrees:6x + 6y = 540To express this equation in terms of x, we can divide both sides by 6:x + y = 90Therefore, the sum of the interior angles of the pentagon in terms of x is 90.