Physics 2017 JAMB Past Questions - Question 23: A capacitor 8μF , is charged to a potential difference of 100V . The energy by the capacitor is

Correct Answer

B

Explanation

The energy stored in a capacitor can be calculated using the formula:

E = (1/2) * C * V^2

Where:
E is the energy stored in the capacitor,
C is the capacitance of the capacitor, and
V is the potential difference across the capacitor.

In this case, the capacitance (C) is 8μF (microfarads) and the potential difference (V) is 100V. Plugging these values into the formula, we get:

E = (1/2) * 8μF * (100V)^2

Calculating this expression, we find:

E = (1/2) * 8 * 10^-6 F * (100)^2 V^2
E = 4 * 10^-6 F * 10000 V^2
E = 40 * 10^-2 V^2
E = 40 * 100 V^2
E = 4000 V^2

Therefore, the energy stored in the capacitor is 4000 joules (J).