PHYSICS
JAMB 2011 - Question 23
Physics 2011 JAMB Past Questions - Question 23: A metal of volume 40cm³ is heated from 30°C to 90°C , the increase in volume is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
E
Explanation
increase in volume, DV = RV1 ? θ = 3α Vsub>1 Dθ
= 3 x 2.0 X 10-5 x 40 x (90 - 30)
= 6 x 10-5 x 40 x 60
0.144 cm3
∴ No correct option

