MATHEMATICS

JAMB 2009 - Question 23

Mathematics 2009 JAMB Past Questions - Question 23: If P = x+1 x-1 ,Evaluate x if |P|=-10

If P = x+1 x-1 ,Evaluate x if |P|=-10
A:
B:
C:
D:
Examkits App

Examkit's JAMB CBT App

Practice JAMB offline with our Online, PC and Mobile App

  • ✅ 25+ years of past questions (2000 to 2025)
  • ✅ Video solutions and explanation to questions
  • ✅ E-library
  • ✅ Study by topic
  • ✅ And more.

Correct Answer

D

Explanation

(x + 3)(x -1) – (x + 2) (x + 1)=(x² + 2x -3) – (x² + 3x + 2)=x² + 2x – 3 - x² - 3x - 2-x – 5 = -10-x = -5 x = 5To evaluate x when |P| = -10, we need to find the value of x that satisfies the equation.Given that P = (x+1)(x-1), we can rewrite |P| as |(x+1)(x-1)|.Since the absolute value of a product is equal to the product of the absolute values, we have:|(x+1)(x-1)| = |x+1| * |x-1|Now, we are given that |P| = -10. However, the absolute value of any number is always non-negative, so it cannot be negative. Therefore, there is no value of x that satisfies the equation |P| = -10.Hence, there is no solution for x in this case.