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MATHEMATICS

JAMB 2013 - Question 2

Mathematics 2013 JAMB Past Questions - Question 2: Find the value of 110111₂ +10100₂

Find the value of 110111₂ +10100₂

A: 1001111

B: 1101011

C: 100101

D: 1001011

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Correct Answer

Explanation

110111+ >10100 1001011₂To find the sum of 110111₂ and 10100₂, we can perform binary addition.``` 110111+ 010100---------```Starting from the rightmost bit, we add the corresponding bits along with any carry:``` 110111+ 010100--------- 1000011```The sum is 1000011₂.Therefore, the value of 110111₂ + 10100₂ is 1000011₂, which is equivalent to 67 in decimal notation.