Mathematics 2007 JAMB Past Questions - Question 2: In a basket ,there are 6 grapes ,11 bananas and 13 oranges. If one fruit is chosen at random ,what is the probability that the fruit is either a grape or a banana?

Correct Answer

C

Explanation

Total fruits = 6+11 +13 =30, prob. (Graape) = 6/30 = 1/5prob.(Banan) = 1/5 +11/30 = 11/30To find the probability of selecting either a grape or a banana, we need to determine the total number of favorable outcomes (grapes and bananas) and divide it by the total number of possible outcomes (all fruits).Total number of grapes = 6Total number of bananas = 11Total number of favorable outcomes (grapes or bananas) = Total number of grapes + Total number of bananas = 6 + 11 = 17Total number of fruits = Total number of grapes + Total number of bananas + Total number of oranges = 6 + 11 + 13 = 30Therefore, the probability of selecting either a grape or a banana is:Probability = Number of favorable outcomes / Total number of possible outcomes          = 17 / 30          = 0.5667 (rounded to four decimal places)So, the probability that the fruit chosen is either a grape or a banana is approximately 0.5667.