Mathematics 2006 JAMB Past Questions - Question 2: A final examination requires that a student answer any 4 out of 6 questions.in how many ways can this be done?

Correct Answer

A

Explanation

To find the number of ways a student can answer any 4 out of 6 questions, we can use the combination formula.The number of ways to choose r items from a set of n items is given by the combination formula:C(n, r) = n! / (r!(n-r)!)In this case, we have 6 questions and the student needs to answer 4 of them. Therefore, we can calculate:C(6, 4) = 6! / (4!(6-4)!)        = 6! / (4!2!)        = (6 x 5 x 4 x 3 x 2 x 1) / ((4 x 3 x 2 x 1) x (2 x 1))        = (6 x 5) / (2 x 1)        = 30 / 2        = 15Therefore, there are 15 ways for the student to answer any 4 out of the 6 questions.