Physics 2013 JAMB Past Questions - Question 19: Two liquids X and Y having the game mass are suppiled with the same quantity of heat .If the temperture rise in X is twice that of Y ,the ratio of specific heat capacity of X to that of Y is

Correct Answer

B

Explanation

To find the ratio of the specific heat capacities of liquids X and Y, we can use the formula:

\(Q = mc\Delta T\)

Where:
Q = Heat supplied to the liquids (assumed to be the same for both X and Y)
m = Mass of the liquids (assumed to be the same for both X and Y)
c = Specific heat capacity of the liquids
ΔT = Temperature rise

Let's assume the temperature rise in liquid X is \(2\Delta T\) and the temperature rise in liquid Y is \(\Delta T\).

For liquid X:
\(Q = mc(2\Delta T)\)

For liquid Y:
\(Q = mc(\Delta T)\)

Since the heat supplied (Q) is the same for both liquids, we can equate the two equations:

\(mc(2\Delta T) = mc(\Delta T)\)

The mass (m) cancels out, and we are left with:

\(2\Delta T = \Delta T\)

Dividing both sides by \(\Delta T\), we get:

\(2 = 1\)

.