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MATHEMATICS

JAMB 2003 - Question 17

Mathematics 2003 JAMB Past Questions - Question 17:

A: -5,-4

B: -4,-5

C: 4,5

D: 5,4

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Correct Answer

Explanation

To find the values of x and y that satisfy the given system of equations:Equation 1: 3x - 5y + 5 = 0Equation 2: 4x - 7y + 8 = 0We can solve this system of equations using the method of elimination or substitution. Let's use the method of elimination:Multiply Equation 1 by 4 and Equation 2 by 3 to make the coefficients of x in both equations equal:Equation 1: 12x - 20y + 20 = 0Equation 2: 12x - 21y + 24 = 0Now, subtract Equation 1 from Equation 2 to eliminate x:(12x - 21y + 24) - (12x - 20y + 20) = 0Simplifying, we get:-21y + 24 - (-20y + 20) = 0-21y + 24 + 20y - 20 = 0-y + 4 = 0-y = -4y = 4Now, substitute the value of y = 4 into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1:3x - 5(4) + 5 = 03x - 20 + 5 = 03x - 15 = 03x = 15x = 5Therefore, the values of x and y that satisfy the given system of equations are x = 5 and y = 4.