Physics 2005 JAMB Past Questions - Question 15: If two inductors of inductances 3H and 6H are arranged in series, the total inductance is

Correct Answer

C

Explanation

L=L1+L2=3+6=9HWhen inductors are arranged in series, their total inductance (L_total) is not simply the sum of their individual inductances. Instead, you calculate it as follows:

1 / L_total = 1 / L1 + 1 / L2

In your case, L1 is 3 H (henries) and L2 is 6 H.

1 / L_total = 1 / 3 + 1 / 6

Now, find a common denominator to simplify the equation:

1 / L_total = 2/6 + 1/6

1 / L_total = 3/6

Now, add the fractions on the right side:

1 / L_total = 1/2

To isolate L_total, take the reciprocal of both sides:

L_total = 2 H

So, when two inductors of 3 H and 6 H are arranged in series, the total inductance is 2 H.