PHYSICS
JAMB 2022 - Question 14
Physics 2022 JAMB Past Questions - Question 14: A transformer which can produce 10V from a 240V a.c supply has an efficiency of 60%. If the current in the secondary winding coil is 15A, the current in the primary coil is
Correct Answer
B
Explanation
To find the current in the primary coil, we can use the formula:
Efficiency = (output power / input power) * 100%
Efficiency = (Pout / Pin) * 100%
Where Pout = Vout * Iout and Pin = Vin * Iin
Given that the transformer has an efficiency of 60%, the output voltage (Vout) is 10V, and the output current (Iout) is 15A. The input voltage (Vin) is 240V.
First, let's find the output power (Pout):
Pout = Vout * Iout
Pout = 10V * 15A
Pout = 150W
Now, we can use the efficiency formula to find the input power (Pin):
Efficiency = (Pout / Pin) * 100%
60% = (150W / Pin) * 100%
Solving for Pin:
Pin = 150W / (60/100)
Pin = 250W
Now, we can find the current in the primary coil (Iin):
Pin = Vin * Iin
250W = 240V * Iin
Solving for Iin:
Iin = 250W / 240V
Iin ≈ 1.04A
So, the current in the primary coil is approximately 1.04A.

