Mathematics 2022 JAMB Past Questions - Question 14: Find the value of k which makes the expression y² +2(k+1)y+k+3 perfect square

Correct Answer

C

Explanation

To find the value of k that makes the expression y² + 2(k+1)y + k+3 a perfect square, we can use the concept of completing the square.The expression y² + 2(k+1)y + k+3 can be rewritten as (y + (k+1))².Comparing this with the given expression, we can equate the corresponding terms:2(k+1) = 2(k+1)This equation is true for any value of k. Therefore, there is no specific value of k that makes the expression a perfect square.In other words, the expression y² + 2(k+1)y + k+3 is already a perfect square, regardless of the value of k.