Mathematics 2001 JAMB Past Questions - Question 14: The sixth term of an arithmetical progression is half of its twelth term.The first term is equal to

Correct Answer

C

Explanation

To find the first term of the arithmetic progression, we need more information. Specifically, we need either the common difference or the values of the sixth and twelfth terms.However, we can still provide a general solution using a variable. Let's assume the first term of the arithmetic progression is "a" and the common difference is "d".The formula for the nth term of an arithmetic progression is given by:Tn = a + (n - 1) * dGiven that the sixth term is half of the twelfth term, we can write the following equation:a + 5d = (1/2)(a + 11d)Simplifying the equation:2a + 10d = a + 11da = dSince we don't have any specific values, we can express the first term in terms of the common difference. Therefore, the first term is equal to the common difference (a = d).Please provide additional information if you want a more specific answer.