PHYSICS

JAMB 2022 - Question 13

Physics 2022 JAMB Past Questions - Question 13: Two masses 50g and 70g are suspended from the respective ends of a light metre rule, the centre of gravity of the system is

Choose the correct answers from the options given.
Two masses 50g and 70g are suspended from the respective ends of a light metre rule, the centre of gravity of the system is
A:
B:
C:
D:
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Correct Answer

B

Explanation

To find the center of gravity of the system, we can use the principle of moments. The center of gravity will be located at a point on the meter rule where the moments on either side of that point are equal.

Let's assume the meter rule has a mass of 100g and is 100cm long. The 50g mass is at the 25cm mark, and the 70g mass is at the 75cm mark.

The center of gravity (C.G.) can be calculated using the formula:

C.G. = (m1 * d1 + m2 * d2) / (m1 + m2)

Where m1 and m2 are the masses, and d1 and d2 are their respective distances from the center.

Plugging in the values, we get:

C.G. = (50g * 25cm + 70g * 75cm) / (50g + 70g)
    = (1250gcm + 5250gcm) / 120g
    = 6500gcm / 120g
    = 54.17cm

So, the center of gravity of the system is approximately 54.17cm from one end of the meter rule.