Physics 2013 JAMB Past Questions - Question 13: Calculate the work done when a force of 20N stretches a spring by 50mm.

Correct Answer

A

Explanation

Work done in an elastic string=average force x extension, e = 500mm = 0.05m=1/2 x 20 x 0.05 = 10 x 0. 05 = 0.05J
To calculate the work done when a force stretches a spring, we can use the formula:

Work = (1/2) * k * x^2

Where:
- Work is the work done (in joules)
- k is the spring constant (in newtons per meter)
- x is the displacement of the spring (in meters)

In this case, we are given:
- Force = 20 N
- Displacement = 50 mm = 0.05 m