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MATHEMATICS

JAMB 2017 - Question 13

Mathematics 2017 JAMB Past Questions - Question 13: Differentiate y = 3cos 2x - sin4x.

Differentiate y = 3cos 2x - sin4x.

A: -6sin 2x + 4cos4x

B: 6sin2x +4cos4x

C: -6sin2x -4cos4x

D: 6sin2x -4cos4x

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Correct Answer

Explanation

y = - 6 5m 2x - 4 cos4xTo differentiate y = 3cos(2x) - sin(4x) with respect to x, we can use the following differentiation rules:The derivative of cos(ax) with respect to x is -a*sin(ax).The derivative of sin(ax) with respect to x is a*cos(ax).Using these rules, we can differentiate each term separately:dy/dx = -3*2*sin(2x) - 4*cos(4x) = -6sin(2x) - 4cos(4x)So, the derivative of y = 3cos(2x) - sin(4x) with respect to x is dy/dx = -6sin(2x) - 4cos(4x).