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MATHEMATICS

JAMB 2005 - Question 13

Mathematics 2005 JAMB Past Questions - Question 13: Divide 6x² -13x + 5 by 2x-1

Divide 6x² -13x + 5 by 2x-1

A: 3x+5

B: 3x-5

C: 5x-3

D: 5x+3

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Correct Answer

Explanation

To divide the polynomial 6x² - 13x + 5 by 2x - 1, we can use polynomial long division. 3x - 2 _______________2x - 1 | 6x² - 13x + 5First, we divide the leading term of the dividend (6x²) by the leading term of the divisor (2x), which gives us 3x. We write this as the first term of the quotient.Next, we multiply the divisor (2x - 1) by the quotient term (3x) and subtract it from the dividend (6x² - 13x + 5). 3x - 2 _______________2x - 1 | 6x² - 13x + 5 - (6x² - 3x) _______________ -10x + 5Now, we bring down the next term from the dividend (-10x) and repeat the process. 3x - 2 _______________2x - 1 | 6x² - 13x + 5 - (6x² - 3x) _______________ -10x + 5 - (-10x + 5) _______________ 0Since the remainder is 0, we have successfully divided the polynomial.Therefore, the quotient is 3x - 5 and there is no remainder.