Physics 2002 JAMB Past Questions - Question 12: A particle in circular motion performs 30 oscillations in 6 seconds ts angular velocity is

Correct Answer

A

Explanation

w=2πF=2*π*30/6=10πrad/sTo find the angular velocity of a particle in circular motion, you can use the formula:

Angular velocity (ω) = (2π * Number of oscillations) / Time

In this case, the particle performs 30 oscillations in 6 seconds, so you can plug in these values into the formula:

Angular velocity (ω) = (2π * 30) / 6

Angular velocity (ω) = (60π) / 6

Now, simplify the expression:

Angular velocity (ω) = 10π radians per second

So, the angular velocity of the particle in circular motion is 10π radians per second.