MATHEMATICS
JAMB 2015 - Question 11
Mathematics 2015 JAMB Past Questions - Question 11: In how many ways can the letter in the word ELATION,be arranged?
Correct Answer
C
Explanation
4(x-2)<8(x+3)4x < 32 =x> -84 -4The word "ELATION" has 7 letters, but it has repeated letters. To find the number of ways the letters in the word "ELATION" can be arranged, we can use the concept of permutations.The word "ELATION" has the following letters:E - 1L - 1A - 1T - 1I - 1O - 1N - 1To find the number of arrangements, we can use the formula for permutations of a word with repeated letters, which is given by:n! / (n1! * n2! * n3! * ...)Where n is the total number of letters, and n1, n2, n3, ... are the number of repetitions of each letter.Using this formula, the number of arrangements for the word "ELATION" is:7! / (1! * 1! * 1! * 1! * 1! * 1! * 1!)= 7! / 1= 7 * 6 * 5 * 4 * 3 * 2 * 1= 5040Therefore, the letters in the word "ELATION" can be arranged in 5040 ways.

