MATHEMATICS
JAMB 2003 - Question 10
Mathematics 2003 JAMB Past Questions - Question 10: Find the variance of 2, 6, 8, 6, 2 and 6
A:
B:
C:
D:
Correct Answer
B
Explanation
mean of X = x = (2+6+8+6+2+6)/6 = 30/6 = 5X → 2,6,8,6,2,6X - x = -3, 1, 3, 1, 3, 1(X - x)2 = 9, 1, 9, 1, 9, 1∑(X-x) = 9+1+9+1+9+1 = 30Variance = ∑(X-x)2/n = 30/6 = 5

